Consider the cell at 25 degree celsius
WebConsider the cell A g (s) ∣ A g B r (x) ∣ B r − (a q) ∣ ∣ C l − (a q) ∣ A g C l (s) ∣ A g (s) at 25 o C. The solubility product constants of A g B r and A g C l are 5 × 1 0 − 1 3 and 1 × 1 0 − 1 0 respectively. For what ratio of the concentrations of Br − … WebThe potential of the following cell at 25 ∘C is: Pt ∣∣∣∣∣∣ H 2(1atm)∣∣∣∣∣∣HNO 30.1M∣∣∣∣∣∣∣∣∣∣∣∣ NaOH(10 −3M)∣∣∣∣∣∣ H 2(1atm)∣∣∣∣∣∣Pt A −0.059V B 0.059V C - 0.59V D 0.5V Medium Solution Verified by Toppr Correct option is C) It is a concentration cell, therefore, E cell⊖=0 . pH of HNO 3=−log10 −1=1 pOH of NaOH = −log10 −3=3 ∴ pH of NaOH =14−3 =11
Consider the cell at 25 degree celsius
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WebClick here👆to get an answer to your question ️ 4.23 Consider the following cell Pb(s) Pb2+(0.5M) Cu2+(0.001M) Cu (a) Write the cell reaction. (b) Calculate Écell and Eºcell at 25°C. (c) Calculate AG and AGº for the cell reaction [(b) Eºcell = 0.463V, Ecell = 0.383V, (c) AG° = -89.4 kJ, AG = -73.92 kJ] 4.24 Consider the followinn WebOct 24, 2024 · Step 4: Determine E° cell = E° cathode - E° anode. = 1.065 - (-1.676) = 2.741 V. Step 5: Once E° cell has be calculated and the number of moles of electrons have been determined, we can use ∆G = -nFE° …
WebMay 17, 2024 · Rmm = 8.314J⋅K-1mol-1 T mm = 25 °C = 298.15 K ΔS∘l = -269 J⋅K-1mol-1 Thus, lnK = - -103 800J⋅mol-1 8.314J⋅K-1mol-1 × 298.15K + -269J⋅K-1mol-1 8.314 × J⋅K-1mol-1 = 41.7 - 32.36 = 9.52 K = e9.52 = 1.36× 104 Answer link WebCalculate E degree_cell; Question: Consider the following cell at 25 degrees C: Mn(s) Mn^2+ (aq, 1 M) ClO_2^-(aq, 1 M) ClO_2(g) Pt(s) For data consult Table 19.1 …
WebJan 10, 2024 · This table is an alphabetical listing of common reduction half-reactions and their standard reduction potential, E 0, at 25 C, and 1 atmosphere of pressure. The standard reduction potentials are all based … WebConsider a voltaic cell in which the following reaction takes place in basic medium at 25°C. 2NO3-(aq)+3S2(aq)+4H2O3S(s)+2NO(g)+8OH(aq) (a) Calculate E°. (b) Write the Nernst …
WebA voltaic cell is constructed at 25 °C from a half-cell in which a nickel rod is dipped into a solution of nickel (II) nitrate, and another half cell in which a chromium rod is dipped into a solution of chromium (III) nitrate. The two half-cells are connected by a salt bridge. Write the reduction half-reaction.
WebOct 24, 2024 · E° cell: Standard Cell Potential E° cell is the electromotive force (also called cell voltage or cell potential) between two half-cells. The greater the E° cell of a reaction the greater the driving force of electrons … onclick triggering twiceWebFeb 1, 2024 · What is the equilibrium constant of the combined cell reaction at 25 C? Solution Step 1: Combine and balance the two half-reactions. The oxidation half-reaction produces 2 electrons and the reduction half-reaction needs 6 electrons. To balance the charge, the oxidation reaction must be multiplied by a factor of 3. onclick triggered without clicking reactWeb(J/ K. mol) Ag+ (aq) CI- (aq) AgCI (s) 105.90 167.2 127.0 73.93 56.5 96.11 The value of K for the reaction at 25 °C is A) 810 B) 1.9×10-10 C) 5.3 x 109 D) 3.7 x 1010 E) 1.8 x 104 11) What is the oxidation number of This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. onclick trigger 2 functionsWebThe Nernst equation for the cell reaction at 25 ºC will be E c e l l = E c e l l o − 0. 0591 n log [ Z n 2 +] [ H +] 2 = 0. 76 − 0. 0591 2 log 0. 001 ( 0. 01) 2 = 0. 76 − 0. 02955 ( log 10) = 0. 76 − 0. 02955 ( 1) = 0. 73045 V ≈ 0. 73 V Thus, the emf of the cell at 25 ºC is 0.73 V. Concept: Galvanic or Voltaic Cells - Introduction is a us will valid in canadaWebA voltaic cell in set up at 25^oC with the following half cells: Al/Al^3 + (0.001 M) and Ni/Ni^2 + (0.50 M) Write an equation for the reaction that occurs when the cell generates an electric current and determine the cell potential. ENi^2 + /Ni = - 0.25 V and E^oAl^3 + /Al = - 1.66 V (log (8 × 10^-6) = - 0.54) Class 12 >> Chemistry onclick trong htmlWebQuestion: Consider the standard cell at 25 degrees Celsius based on the following half reactions. Pb^(2+) + 2e- > Pb Eofcell = -0.13V Zn^(2+) + 2e- > Zn Eofcell = -0.76V To … is aut a good universityWebExample: Find the value of the equilibrium constant at 25 o C for the cell reaction for the following electrochemical cell: Cu Cu 2+ (1 M) Ag + (1 M) Ag. (The solution for the determination of the E o cell and the number … onclick trong js