http://getteched.com/ WebFeb 23, 2024 · Node* head = NULL; int i; for (i = 5; i > 0; i--) push (&head, i); cout << " list before: "; printList (head); setMiddleHead (&head); cout << " list After: "; printList (head); …
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WebJan 23, 2015 · The GetHead() function is as follows: nodePtr List::GetHead(){ return head; } When I compile, I get . error: unknown type name 'nodePtr' error: cannot initialize return object of type 'int' with an lvalue of type 'nodePtr' (aka 'List::node *') Is there a problem in how I am returning the pointer to the struct node?WebMay 31, 2024 · Node* n = new Node (5) Then the list is existing and from now on you can add new members with calling appendToTail. There are more semantic errors in your code which have luckily no side effects. You must not delete the 'end' variable in your function. You want to keep the newly allocated memory for the new tail. * -size: int ----- +rLL() +~rLL() +getHead(): ... • getHead: This returns the head pointer of the linked list. • push: This adds a new item to the linked ...lazlo witches hat